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Triangulation
Posted by Hamlet on 5 Aug at 8:00AM
A man starts from the North Pole and walks 6 miles in a straight line. He then faces East and walks 8 miles in a straight line. He then returns to the North pole in a straight line. How many miles did he walk altogether?

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Re: Triangulation
Posted by Hypnotician on 5 Aug at 9:09AM
6 + 8 + 6 = 20 miles.

-Ray.

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Re: Triangulation
Posted by HMMcGonagall on 12 Aug at 9:34PM
wouldn't the last six miles be NW perse going back to the NP?

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Re: Triangulation
Posted by fatdaddy on 12 Aug at 9:58PM
The rotational North Pole is directly north from any point on Earth (except for itself) ...until you start talking about the magnetic North Pole....

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Re: Triangulation
Posted by Aphrodite on 5 Aug at 10:26AM
24 miles. And the poor man probably got frost bite LOL

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I agree
Posted by p24601 on 5 Aug at 5:30PM
I agree. 24 miles. But it won’t be easy, and we might disagree on the details.

The earth is curved, so he can’t stay on the earth’s surface by walking in a straight line. Either there is a conveniently placed 6-mile-long chord-tunnel, or chord-ditch, that slices underground a small amount and returns to the surface after 6 miles, or he has mastered the art of walking on air, and traces a tangent line. There are other possible straight line directions, but these seem to be the most feasible, and they all face South, unless he walks straight up to the zenith. But let's be realistic -- no one can do that. ;-)

He faces East and walks 8 miles in a straight line. It doesn’t say that he continues to face East while he is walking, so he is not following a latitudinal path, but is getting somewhat further from the North Pole during this 8 mile segment. Again, he is either walking in a tunnel, or walking on air. It doesn’t matter which.

Since his original 6-mile segment was due South, whether below or above the surface, and he began his 8-mile segment facing East, those segments are perpendicular in 3-dimensional space. His return to the North Pole is a straight line. Therefore, whether below or above the surface, his overall trace is that of a triangle in 3-dimensional space, with one angle being a right angle. Because of the formula due to that Pythagoras dude (though he lived no where near the North Pole), the final segment is 10 miles, for a total trip of 24 miles.

He may be cold when he returns to Santa’s house, and he may be either lighter than air, or else he needs to wait while his eyes return to their normal dilation from walking under the surface of the earth. Unless he carried a light source with him. Of course.

;-)

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Re: I agree
Posted by FragileKitty on 5 Aug at 7:24PM
Your logic is surprisingly compelling (I originally answered as Hypnotician did). I had some trouble following that the first segment was due south until I realized that due south doesn't mean straight down toward the South Pole. Whatever angle that is, "east" from there must be perpendicular, and so you get the right triangle.

Very impressive!

I wonder if we can map this to 4D space now and somehow make traveling along the surface of a 3D sphere into straight lines and get the more intuitive answer of 20 miles ;)

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Re: I agree
Posted by Hamlet on 6 Aug at 6:38AM
I didn't really expect the poor man to go to quite so much trouble. He may be a bit adventurous but he is not a mining engineer. Let's take it for granted that by North Pole, we mean a point on the earth's surface and that walking in a straight line has its usual meaning when walking on the earth's surface (would walking on the circumference of a great circle do?) If you want to calculate the exact distance travelled taking into account the curvature of the earth's surface, please feel free to do so but again I'll accept the common sense answer. :)

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Re: I agree
Posted by Hypnotician on 6 Aug at 6:16PM
You wrote:
... I'll accept the common sense answer. :)

Which is what? :)

-Ray.

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Re: I agree
Posted by FragileKitty on 6 Aug at 6:43PM
It has to be your answer, Ray :)

I find the more I try to think through the "complicated" answer the more I confuse myself ;)

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Re: I agree
Posted by Hamlet on 6 Aug at 6:51PM
Change miles to feet and see what you think!

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Re: I agree
Posted by Hypnotician on 6 Aug at 7:11PM
I was teasing the original poster a bit. :)
I appreciate the official answer being supplied by the original poster after a few days for closure. LOL!

-Ray.

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Re: I agree
Posted by FragileKitty on 6 Aug at 7:51PM
I now withdraw everything I've said. Geometry and I have never really gotten along ;)

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Re: I agree
Posted by p24601 on 6 Aug at 9:05PM
My ideas about tunnels and ditches were put forth with my tongue firmly in cheek. I was poking fun at too literal interpretations. A straight line can certainly mean walking a great circle path. ;-)

However, the rest is up for debate, it seems to me. That's because you state that he turns east, then walks in a straight line. You don't say that he continues to face east as he walks. In fact, if he did continue to face east as he walks, it would not be a great circle route (and not a straight line by your definition), but one that followed a certain latitude. So I maintain that he faced east, walked in a straight line that made him further from the north pole, then finished with a 10 mile walk for 24 miles total (and that might not be exact because of the slight weirdness of spherical trigonometry). If the problem statement was "He walked toward the east for 8 miles" that would be a different statement, IMHO. I don't think that I am being "too literal" there -- only trying to interpret in a straightforward way what the components of the problem are.

It certainly does highlight the ambiguities of language, doesn't it?

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Re: I agree
Posted by Hamlet on 7 Aug at 6:55AM
Where's the ambiguity? I thought I had worded the question so there would be none. He walks 6 miles in a straight line (necessarily South), turns 90º (faces East) walks 8 miles in a straight line which leaves him 10 miles from the North Pole. Total distance walked equals 24 miles. Your answer is correct. No question about it.

Of course I was expecting the 20 miles answer, but as you point out yourself walking along a line of latitude cannot be considered walking in a straight line which becomes obvious if you think of 6 feet rather than 6 miles.

I think the perceived ambiguity lies in our concept of East and West. My hometown of Southampton lies pretty much on the same latitude as Vancouver in Canada (50ºN) So is Vancouver due West from here? If I start off on a Westerly bearing and maintain my straight line, I will end up in Mexico. The correct bearing to get to Vancouver is nearer North West. Directions are strange concepts.

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Re: I agree
Posted by superkaempe the gentle giant on 7 Aug at 8:12AM
It is commonly accepted that east/west at any point is perpendicular to the meridian you are at so that the only way you can go east (or west) in a straight line is at the Equator. That also means that anything due west (or east) of you will be at the same latitude as you are.

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Re: I agree
Posted by Twakkie on 14 Aug at 5:46PM
Sorry Hamlet, but I don't agree. 24 miles is not correct.

If you walk 6 miles south, then you are, well, 6 miles south of the north pole. If you then turn 90 degrees and face east and start walking due east for 8 miles - you are still just trudging along on a straight line which is ALWAYS still only 6 miles south of the north pole. You can follow this line right around the earth and you will always be just 6 miles south of the north pole. The Pythagoras-triangle-principle-thing does not work in this case.

Hypnotician was therefore correct in stating that the answer is 6 + 8 + 6 which gives 20 miles.

Try to convince me otherwise!

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Re: I agree
Posted by Hamlet on 14 Aug at 6:07PM
Try replacing miles by feet. Draw a circle of radius 6 feet around the North Pole and imagine walking around it. Are you walking in a straight line?

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Re: I agree
Posted by Sir Tytalus of the GoldTable on 15 Aug at 6:28AM
I guess it depends on the exact phrasing..


If you say "faces due east and walks x distance in a straight line" that would imply that you are walking on the tangent.

However, if you say "walks x distance due east" that would imply (to me) that you are making continual adjustments and walking the geodesic....

;-)

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Re: I agree
Posted by Hamlet on 15 Aug at 8:56AM
That's why I said He then faces East and walks 8 miles in a straight line. ;-)

On a sphere a geodesic is a straight line, a line of latitude is not.

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Re: I agree
Posted by Twakkie on 15 Aug at 9:41AM

try replacing your 6 mile number with the distance equal to the distance between the north pole and the tropic of cancer, for example...if you the travel east along that line you will ALWAYS be the same distance from the north pole! even if you travel half way around the globe...

in your example you clearly state that you turn only 90 degrees, therefore you have to follow the line of latitude...and will still be the same distance from the north pole.

i learned this from a riddle that states: you are at your camp. you walk 3 miles directly south, then again 4 miles directly east, and then 3 miles directly north again, only to find that you are back at your original camp site! the question is: what colour are the bears?

and the answer, of course, is white (polar bears) because your camp site is on the north pole!

lol!

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Re: I agree
Posted by FragileKitty on 15 Aug at 9:46AM
I remember that riddle :)

It works for your riddle because you walk directly east. That's different from facing east and walking in a straight line. The only latitude where walking in a straight line is the same as walking east is on the equator.

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Re: I agree
Posted by Twakkie on 15 Aug at 9:49AM

then the clues are wrong! it clearly states you turn 90 degrees! if only 6 miles south and then face east (as in 3 o'clock when facing the globe) the turn is more than 90 degrees...

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Re: I agree
Posted by Hamlet on 15 Aug at 10:10AM
Yes, you do turn 90º. That's the whole point.

If you walk 6 miles in a straight line, turn 90º walk 8 miles in a straight line, you will always be 10 miles from where you start by Pythagoras's theorem. It doesn't make any difference whether you are at the equator or a pole or anywhere else. The mistake you are making is that if you turn 90º you will be walking along a line of latitude but that just isn't true.

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Re: I agree
Posted by Twakkie on 16 Aug at 2:57AM
it does make a difference if a pole is your starting point...

lets extend your example to the equator: you are at the north pole. you travel south until you reach the equator. you then turn 90 degrees and move east - how far does not really matter - but for argument's sake lets assume it is one third of the length of the equator. how far are you from the north pole (which was your starting point)?

easy - exactly as far as you were when you turned east! which implies that the distance you travelled since you turned 90 degrees is irrelevant in terms of your distance to your starting point of the north pole. can't be anything else!

the mistake you are making is ASSUMING that the theorem of Pythagoras also holds true on the surface of a sphere - which it certainly does not! the theorem is only valid for two-dimensional triangles, not three-dimensional...

you are ignoring the basic geometric principles of a sphere/globe in your argument...once you turn 90 degrees you will definitely be walking along a line of latitude...else your turn is not a true 90 degree turn but a slightly bigger angle.

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Re: I agree
Posted by Hypnotician on 16 Aug at 9:49AM
They keyword in the original problem was straight line. Here's a hint to the other side of the argument: imagine a right triangle with indicated sides and with one corner attached to the North Pole. The triangle does not bend to fit against the Earth's surface. The straight lines are indeed straight lines.

I didn't see this when I offered my original answer, but p24601 gave a compelling answer a while back. Of course, the answer was not very practicial. :)

-Ray.

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Re: I agree
Posted by Twakkie on 16 Aug at 2:34PM
if you super-impose a triangle onto the earth's surface, it would theoretically not fit as the earth is not completely flat and the triangle is. therefore for you to walk along the lines the triangle creates will lead to you walking on air!

i don't understand how you all can't get it!!!

the angles where a line of latitude and longitude crosses are all exactly 90 degrees (check any map!). therefore turning 90 degrees will lead one to travel along a line of latitude. if it does not then the turn was not 90 degrees!

and moving along a line of latitude will always leave you the same distance from the pole.

sorry - but all of you who agree the answer is 24 are WRONG! it is 20 in the given question.

i am now going to stop flooding this board with my posts as it is a riddle and puzzle board and not a whining session.

anyone who still wishes to disagree with me or just discuss the issue are welcome to PM me.

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Re: I agree
Posted by superkaempe the gentle giant on 16 Aug at 3:00PM
It is quite simple actually, a curve and its tangent have the same direction at the tangent point, but that means that a line perpendicular to the tangent at that particular point is also perpendicular to the curve. Now in this problem the line of latitude is the curve and the geodesic is the tangent. When you reach the tangent point you follow the tangent and not the curve. You still start out to the east, but as soon as you have left the tangent point your direction is not east any more. I had problems with this myself until I started viewing it as a calculus problem. It is however also correct that the distance back to the north pole is not exactly 10 miles because we are on a sphere, but if we are not counting fractions of miles then 10 miles is the closest result we can get.

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Re: I agree
Posted by p24601 on 16 Aug at 3:02PM
It's all about agreeing what is meant by a straight line. I just don't see an interpretation of a straight line as following a latitude trace anywhere but at the equator. The more natural interpretation is that a straight line traces a great circle route. The only time a non-equator latitude trace looks like a straight line is on a Mercator map projection. Every map projection is a lie in some sense, because you can't lay down a sphere onto a plane without distorting something, but the trick lies in understanding what the characteristics are, and how they can be used for a particular purpose, like dead reckoning navigation against the stars, equal areas, or equal distance, etc.

If the first leg of the journey is 6 feet, you face east and then follow a latitude trace until you circle the pole several times, you will end up dizzy very fast. I maintain that you don't end up dizzy by walking in a straight line, unless you have questionable endurance like me. :)

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Re: I agree
Posted by FragileKitty on 16 Aug at 3:05PM
I knew the dizziness conjecture would explain everything. Thank you. I am no longer dizzy..., er..., confused.

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Re: I agree
Posted by Hamlet on 16 Aug at 3:55PM
I think we are so used to looking at a Mercator projection map that we take for granted that if we follow a bearing of East, we are travelling in a straight line. Of course it works very well for small distances away from the poles, but it breaks down for large distances or any distance near the poles. The idea that if you walk South from the North pole, turn 90º and keep walking straight you will evenually come to the equator is very counter-intuitive. A quick look at a globe (or a football - soccerball?) shows that this is so however. (use a piece of string to define a 'straight line')

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Re: I agree
Posted by Twakkie on 18 Aug at 8:49AM
Hi there - me again...

Contrary to me saying I would leave this alone - I would like to take this further. I don't like people reading this and forming incorrect opinions and therefore I will not let it rest.

Have a look at the following link:
http://www.absoluteastronomy.com/encyclopedia/s/sp/spherical_geometry.htm

A quick excerpt:
**********start quote
Spherical geometry is the geometry of the two-dimensional surface of a sphere. It is an example of a non-Euclidean geometry.

In plane geometry the basic concepts are points and lines. On the sphere, points are defined in the usual sense. The equivalents of lines are not defined in the usual sense of "straight line" but in the sense of "the shortest paths between points" which is called a geodesic. On the sphere the geodesics are the great circles, so the other geometric concepts are defined like in plane geometry but with lines replaced by great circles. Thus, in spherical geometry angles are defined between great circles, resulting in a spherical trigonometry that differs from ordinary trigonometry in many respects (for example, the sum of the interior angles of a triangle can exceed 180 degrees).
**********end quote.

And this is exactly where your whole argument falls flat! A triangle on the surface of a sphere does not have the usual 180 degrees in the sum of its angles. Therefore it is INCORRECT to use the theorem of Pythagoras.

Think of it this way - if you go straight south from the north pole to the equator - and turn 90 degrees - you have one right angle. If you then keep travelling east along the equator (we have already agreed that there will be no deviation from this line of latitude as it is on the east-west plane) for a distance, and then turn 90 degrees north again - which happens to be the shortest route back to the north pole! When you reach the north pole and trace your route you will see that you have a semblance of a triangle with TWO (yes, count them!) TWO right angles! Pythagoras just turned in his grave as the penny dropped. LOL!

And what is good for the equator as a line of latitude is valid anywhere else on any other line of latitude.

I eagerly await your responses...

Twakkie.

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Re: I agree
Posted by FragileKitty on 18 Aug at 9:21AM
I'm very glad you are defending your argument. While I excelled in Calculus in college, I don't remember half of it, and my one highschool course in Geometry was the one math course I had trouble with. So I don't know the correct answer to this problem. You all are providing compelling arguments. I'd be hard-pressed to argue with superkaempe the gentle giant though ;)

This is a simple geometry problem. The answer is in the math. Wish I knew the math for this!

Applying logic, I agree with you that the curved surface of a sphere changes things. The question is, does it change things just a little, or enough to make it so facing east and traveling in a straight line keeps you on the same latitude? You say yes; others say no. Everyone agrees that the sum of a triangle's angles on a sphere's surface are greater than 180 degrees. But you all differ on how much. You say it's enough to form two right angles, and others say it's just slightly over 180 degrees, and rounding down you get 180 degrees. My intuition keeps flip-flopping when I think this through.

So who knows the math? :)

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Re: I agree - The Maths
Posted by Hamlet on 18 Aug at 3:25PM
The maths is a lot simpler than I feared.
The spherical equivalent of Pythagoras' theorem is

cos a = cos b cos c

where a,b,c are the sides of the triangle expressed as radians of arc (a is the hypotenuse)

Lets assume the radius of the earth is 4000 miles

Then with a little help from a spreadsheet we can calculate the hypotenuse for various 3,4,5 triangles. These are all in miles. We can see from this that the error is very small indeed until we get to around 1000 miles.


Side 1 Side 2 Pythag Actual
3 4 5 4.9999997
6 8 10 9.9999976
60 80 100 99.99759987
120 160 200 199.9807959
600 800 1000 997.5870846
1200 1600 2000 1980.383381
6000 8000 10000 6165.420044
6283.18 8377.573333 10471.96667 6283.182654

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Re: I agree - The Maths
Posted by superkaempe the gentle giant on 18 Aug at 3:40PM
I grapped my calculator to see how much the difference was for the 6-8-10 miles triangle, it is between 0.15 and 0.16 inch.

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Re: I agree - The Maths
Posted by Hamlet on 18 Aug at 3:44PM
Right or about 4mm.

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Re: I agree - The Maths
Posted by p24601 on 18 Aug at 4:08PM
Very, very cool. But what about the oblateness of the earth ellipsoid? j/k

But, as FragileKitty says, the basis of disagreement is whether you consider "face east" to mean that you then continue to face east as you walk the line. As the quoted description of spherical geometry says, the shortest distance between two points on a sphere is along a great circle route. The most natural description of a straight line on a sphere is that of the shortest distance between two points. And I do like her illustration with toothpicks and popsicle sticks also.

The only way to make a non-equatorial latitude appear to be a straight line is from a vantage point somewhere on the plane that intersects that latitude.

But back to my dizzyness thingy. Let's make the first leg of the trip 2 feet, to make sure we fall into the dizzyness domain. If we follow this latitude trace/curve/line, at about 89 deg, 59 minutes, 59.999 seconds or so, and continue to where we started, the distance is 2 * 2 * pi, approximately 12.566 feet. But we don't really have to go to the north pole to check this. By a translation and rotation of spherical coordinates, we can do the experiment right where we are. The only thing special about the north pole is that it sits on that invisible axis of rotation. OK, mark the surrogate north pole, and a 2 foot line heading to virtual south. Then draw the equivalent to the latitude trace which ends up looking an awful lot like a circle. You can use popsicle sticks if you wish. I challenge anyone to follow this strange line that looks sort of like a, pardon the expression, circle, around to its starting point, and continue this many times. Each time you finish a cycle, call out, "I am still walking in a straight line".

Yes, yes, I am admittedly being silly, and walking a great circle route is also tracing a circle. But the point remains, with the natural semantics of the problem as stated, the total distance is 24 miles.

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Re: I agree - The Maths
Posted by Hamlet on 18 Aug at 7:56PM
Exactly. Actually this problem is a lot clearer if we word it somewhat differently as follows.

A man is put down somewhere on the surface of the earth. He walks 6 miles in a straight line (any direction),turns 90º left, walks 8 miles in a straight line. How far is he in a direct line from where he started? The answer is obviously 10 miles. Since we're assuming the earth to be spherical, the point on the earth's surface and the directions travelled in are all irrelevant to the problem. The only possible concern is whether using the 2-dimensional Pythagoras theorem is a valid approximation and as we have seen it is accurate to a fraction of an inch.

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Re: I agree - The Maths
Posted by Twakkie on 19 Aug at 7:39AM
google for "haversine formula".

this is the correct formula to use.

but since this formula calculates the distance between two points, and you need the latitude and longitude of both, I guess we are back to square one as we will always disagree on the latitude and longitude of the second point...

stalemate.

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Re: I agree - The Maths
Posted by Hamlet on 19 Aug at 8:08AM
We can't use the haversine formula, as we don't know the lat and long of all the points. However we've agreed that we turn through a right angle, so we can use the formula for spherical right-handed triangles which is what I did.

The derivation of this formula can be found at

http://www.maths.soton.ac.uk/staff/AEHirst/ma208/notes/sphere.pdf

or an html version at

http://www.google.com/search?q=cache:xm5NawZTrUcJ:www.maths.soton.ac.uk/staff/AEHirst/ma208/notes/sphere.pdf+spherical+Pythagoras+earth+triangle&hl=en

The formula appears under the heading Right-angled Spherical Triangles on Page 4.

Regards

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Re: I agree - The Maths
Posted by Twakkie on 19 Aug at 11:19AM
the only formula to use here is the haversine formula. the waypoints can all be calculated from the information given. the only argument would be the exact location of waypoint number 2...

the reason the spherical right handed triangles derivation of the pythagoras theorem does not work is because it is based on a principle of the three sides of the triangle all lying on great circles. re-read the definition of a great circle. its centre point is also the middle of the earth, i.e all longitudinal lines and also the equator are great circles. the bottom line of your triangle is not a great circle as defined, but rather a geodesic. which means the formula based on pythagoras does not work.

homework for the weekend:

get hold of a gps navigation device somewhere - beg, borrow, steal!
program your starting point to be the north pole.
put in the 6 miles south.
get the waypoint.
calculate the distance. (hint: should be 6 miles!)
put in the second leg of the route of 8 miles east from that waypoint.
get the new waypoint.
calculate the distance. (hint: should be 8 miles!)
now put in the return leg to your starting point.
calculate the distance. (hint: if the answer happens to be 6 miles, don't break the gps - it is in perfect working order!!!)

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Re: I agree - The Maths
Posted by Hamlet on 19 Aug at 11:33AM
A geodesic is a great circle. They are the same thing. ie a straight line.

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Re: I agree - The Maths
Posted by Twakkie on 21 Aug at 3:50AM
OK - Sorry. Got hung up on the semantics there.

The point I was trying to make is that the bottom line of the triangle is not a great circle in your given example. Therefore it is incorrect to use the spherical equivalent of the Pythagoras Theorem as it only holds true if all three sides of the spherical triangle are on great circles. Clearly in this case the bottom line of the triangle is not a great circle.

Sorry for the confusion with the terminology. I am trying to explain something which I know to be correct, in mathematical terms that are unfamiliar. I suppose we are all learning as we go along here!

Have you managed to get hold of a GPS device yet?

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Re: I agree - The Maths
Posted by superkaempe the gentle giant on 21 Aug at 4:30AM
Except for the poles you can at any point of the earth find a great circle which at that particular point and half way round the planet and nowhere else (except for the equator) has the direction east-west. When you come from north and turn east you can follow that great circle, and unlike an latitudinal circle it will at every point at it be perpendicular to the longitudinal circle you came from. People often forget that it is possible to start in the direction of a curve and follow a straight line without turning, not only on a plane surface but also on a sphere

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Re: I agree - The Maths
Posted by Twakkie on 21 Aug at 5:28AM
i will post the thread elsewhere to make it more readable.

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Re: I agree - The Maths
Posted by FragileKitty on 19 Aug at 11:39AM
I just looked up "geodesic" and it says:

(mathematics) the shortest line between two points on a mathematically defined surface (as a straight line on a plane or an arc of a great circle on a sphere) [syn: geodesic line]

I'm confused by what you said. How is the bottom line not lying on a great circle if it is a geodesic?

And doesn't this definition say that the shortest line between two points on a sphere always lies on a great circle (which is not a latitude circle unless it's the equator)?

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Re: I agree - The Maths
Posted by superkaempe the gentle giant on 19 Aug at 11:45AM
Yes on a sphere the shortest distance between two points is a great circle. That is also why it is not shortest to fly directly east-west between 2 points at the same latitude (except if it is the equator) but at the northern hemisphere you go north of that latitude.

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Re: I agree - The Maths
Posted by Hamlet on 19 Aug at 11:57AM
Right. This is why planes from Europe to the US often fly over Greenland but ships travelling on a West bearing don't go anywhere near it.

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Re: I agree
Posted by Hamlet on 18 Aug at 9:22AM
You are quite correct that ordinary geometry does not apply on the surface of a sphere. You are also correct that if I had said 6000 miles and 8000 miles, the distance back would be 6000 miles for a total trip of 20000 miles (more or less). This is because with such large distances, Pythagoras' theorem does indeed break down. However with small distances the error is very small and in this respect one position on a sphere is the same as any other. The key to understanding this problem is simply that a line of latitude is not a straight line (except the equator of course).

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Re: I agree
Posted by Twakkie on 18 Aug at 11:22AM
Surely you must realise the errors and flaws in your argument!

You are saying I am correct for great distances and on the equator, but not for smaller distances...

Surely you must realise that for something to be a given, it needs to work in ALL circumstances.

If you work in feet, for example, you will walk 6 feet south and 8 feet east. What you don't realise is that by turning 90 degrees east, you will in fact be following the line of latitude and walk in a circle around the north pole. As silly as this sounds, it is actually correct. You are confused because walking in what you think is a circle does "not feel right" because you are supposed to be walking in a straight line! If you read the link I gave earlier you will see that these circles around the sphere are in fact straight lines!

You are dealing with a sphere here - and the properties are not two-dimensional! Once you grasp that concept you will begin to understand the error of your ways. It is a sphere and has spherical properties, even if you are talking about 6 feet or 6 miles on a sphere the size of earth. The same principle still applies.

Where, in your argument, is the point where you start to be wrong and I start to be right? Is it on the equator? Is it on some arbitrary line? Is it where the numbers start getting big or the man walking starts to get tired? Or where the earth starts to curve? Or where the distance you walked since turning east is bigger than x miles? Come on! Get real!

And a line of latitude is of course a straight line! How can it not be? It is a straight line on the surface of the sphere that curves as the sphere does. Stop thinking about what it looks like (I know it looks like a circle), and start thinking about what it actually is - it is a line tracing around a ball. Simple, actually.

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Re: I agree
Posted by FragileKitty on 18 Aug at 11:43AM
When I view all lines of latitude as circles on a vertical axis, then each circle is indeed a straight line wrapped around the vertical axis (made into a circle), just with different lengths (diameters).

But when I'm on the surface of the sphere, at any latitude other than the equator, a line drawn between me and the north pole which intersects once on the sphere's surface is at a non-vertical angle. To me, this implies that going "straight" will not follow the line of latitude. You're still following a circle, but one that is the same size as the equatorial line of latitude, but now at the altered angle. This "circle" clearly does not follow the line of latitude based on a "vertical" orientation; it intersects it.

To reiterate, traveling "straight" means to traverse the largest possible circle around a sphere.

Now I just said all that as it made sense to me, but now I've found a problem with it. What does "facing east" mean? It seems that if you do travel "straight" along this largest circle, you can't really be facing "east" when you start!

So now I'll propose a new answer: the question is flawed, because there is no way you can face east and travel in a straight line on any latitude other than the equator!

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Re: I agree
Posted by FragileKitty on 18 Aug at 11:47AM
I confuse myself so much it's funny.

Of course you can travel in a straight line when facing "east".

Hmmm...

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Re: I agree
Posted by FragileKitty on 18 Aug at 12:25PM
From any point on the sphere, you have an infinite number of "largest" circles you can travel, in an infinite number of "directions" (or angles of "facing" from a longitudinal line).

Take the angle of "facing" from traversing the latitudinal line (east), and use that same angle of facing to begin your "straight" travel along the largest circle.

Ta da.

So it's not along the latitudinal line.

This now makes perfect sense to me.

Saying every line of latitude not on the equator is a straight line only works if you are not perpendicular to the sphere's surface, but rather always slanted so that you're parallel to the vertical axis of the sphere (and this angle would always have to change). Since it's presumed that you're always perpendicular to the sphere's surface, you must walk in the largest possible circle around the sphere, which can never be on a line of latitude except for the equator.

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Re: I agree
Posted by Twakkie on 18 Aug at 12:48PM
Sorry Kitty but I lost you in there somewhere...lol

I can only explain it to you by saying the following:

Take a two-dimensional (i.e flat) map of the world, not a globe one. Which direction does each and every line of latitude run? East-west. By definition. So in the given example, how would you then travel? Obviously along a line of latitude. You will not be travelling towards the equator side, cause then your direction will be southeast. Agreed?

Now, imagine wrapping that same map around a ball to represent a globe. Do you see it now? Because we are not taught spherical geometry at school (thank goodness!) we can not easily comprehend the three-dimensionality thereof. It feels wrong because you can see it is a curve you are walking on, but in fact it is a straight line around the more curved area of the sphere.

Also remember east and west are not absolutes like north and south. You can keep on going east forever if you wanted to. But if you try going north forever there is some point at which you automaticlly start going south again...East is not the point at which the equator lies when you look at the flat map. It is a direction which is 90 degrees from north.

Hope this helps.

If it is any consolation I also battled with this years ago. Big time. But I managed to figure it out and would like to help anyone that is also struggling with this concept. It is indeed very difficult.

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Re: I agree
Posted by FragileKitty on 18 Aug at 1:28PM
I know my terms aren't proper mathematics.

Take a two-dimensional (i.e flat) map of the world, not a globe one. Which direction does each and every line of latitude run? East-west. By definition. So in the given example, how would you then travel? Obviously along a line of latitude. You will not be travelling towards the equator side, cause then your direction will be southeast. Agreed?

Yes.

Now, imagine wrapping that same map around a ball to represent a globe. Do you see it now? Because we are not taught spherical geometry at school (thank goodness!) we can not easily comprehend the three-dimensionality thereof. It feels wrong because you can see it is a curve you are walking on, but in fact it is a straight line around the more curved area of the sphere.

That only works if you make the map into a vertical cylinder. If you wrap it around a sphere, those latitudinal lines are clearly no longer "horizontal". What you are not taking into account is that the person on the sphere's surface is always perpendicular to the surface, in effect sticking out an angle (not parallel with the north/south axis). If you remain perpendicular to the sphere's surface and walk in a straight line, you'll always form the largest possible circle around the sphere. The view that every line of latitude is a straight line only applies to a cylinder, not a sphere.

Also remember east and west are not absolutes like north and south. You can keep on going east forever if you wanted to. But if you try going north forever there is some point at which you automaticlly start going south again...East is not the point at which the equator lies when you look at the flat map. It is a direction which is 90 degrees from north.

The confusion here lies in "facing" east, and "traveling" east. If you travel east, then yes, you remain on the line of latitude as you say. So what does facing east mean? Imagine a line from the center of the sphere out through the point on the surface where you stand when you want to face east. Your "floor" is a plane perpendicular to the sphere's surface, perpendicular to this line. You will be turning around this line/axis. If you turn 90 degrees, you're not facing east unless you're on the equator. Form a 360 degree circle on the plane from a variety of points and see that this is true. You're only facing east when you stop turning at an angle so that if you were always parallel to the north/south axis when walking around the sphere, you would be on a line of latitude. But since you are not always parallel to the north/south axis (but instead are perpendicular to the sphere's surface), walking in a straight line from a position that initially "faces" east, leaves the line of latitude immediately (unless you're on the equator).

Here's an easy experiment you can do to see my point:

Take a toy globe and a bunch of toothpicks. Align the toothpicks, end-to-end along a line of latitude closer to the north pole than the equator. Make sure that only the center of each toothpick comes into contact with the globe. Notice how the toothpicks are not forming a straight line, they must angle off to follow the circle. Notice how they can only be perfectly straight, end to end, on the equator.

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Re: I agree
Posted by FragileKitty on 18 Aug at 1:40PM
A better experiement might be to use popsickle sticks instead of toothpicks, since they have a width to them. If you make sure each popsickle stick contacts the sphere at it's center point (is flat), and lies along the line of latitude, there's no way you can align them along a straight smooth line, where "unfolding" it would give you a straight line of sticks (except for the equator).

Or do it backwards. Start with a long segment of popsickle sticks all connected end-to-end, on a flat floor. Pick it up and wrap it around into a circle. Now you can put this around any point of a cylinder and it will fit. But on a globe/sphere, it only "fits" on the equator. At other lines of latitude, the popsickle sticks won't lie flat on the globe's surface.

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Re: I agree
Posted by shaper on 19 Aug at 5:28AM
Right everyone - I'm just back from the North Pole.

Went for a wee dander around, tried to walk in straight lines etc.

It's 24 :o)

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Re: Triangulation
Posted by FragileKitty on 19 Aug at 9:32AM
I'm posting up here since the thread has gotten so long :)

Just some idle thoughts on the problem (at the risk of repeating what's already been said earlier):

As first stated by p24601, we can't truly walk in a straight line without leaving the surface of the earth. So we're making some broad assumptions in what "walk in a straight line" means.

Wherever I'm standing is my "local" coordinate system. From my feet to my head is the local vertical Y axis. Stretching my arms out to my side (left and right) is the local horizontal X axis. Points in front of and behind me are on the local depth Z axis. What we're all assuming "walk in a straight line" means is that we never rotate about the local Y axis (that is, we never turn left or right). (It's a given that we never rotate about the local Z axis, for then we'd fall over or do Cleese's silly walk at the least.) However we are always in effect rotating about the local X axis as we walk forward because of the spherical surface we're walking on (actually, our local coordinate system is rotated about this axis).

Once this convention is accepted, the (very close approximation) answer of 24 (as already posted) is correct.

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Re: Triangulation
Posted by Hamlet on 19 Aug at 9:45AM
I agree the essence of walking in a straight line on the earth's surface is bearing neither left or right. This is something we can all do pretty well without any instruments, maps etc. You just keep going straight! It does take some thought to realise that this is equivalent to walking a great circle or geodesic ( ie a maximal circle around the earth) .

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Great idea!
Posted by p24601 on 19 Aug at 3:54PM
I'm going to try to hire John Cleese to do the dizzy walk .....

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Continuation of thread
Posted by Twakkie on 21 Aug at 5:48AM
this is in response to a message posted by superkaempe the gentle giant further down below.


I am going to take your statement and pull it apart and answer each bit seperately, for I believe you have touched on some very important points.

[superkaempe the gentle giant]
Except for the poles you can at any point of the earth find a great circle which at that particular point and half way round the planet and nowhere else (except for the equator) has the direction east-west.

[Twakkie]
Wrong. The exact location of the two points will determine if a east west direction on that great circle is possible. By definition the centre point of a giant circle is also the midpoint of the sphere. The only great circle that can have a east west direction is the equator. Lines of latitude are by definition east west lines, but they are not great circles.

I have just had an idea which might just short-circuit this whole debate.

And I am going to write it in bold to get the point across:

Lines of latitude are by definition lines that are parallel to the equator and also run east west like the equator. So when you initially turn 90 degrees east in the example you are following a line of latitude. Which is also by definition always the same distance from the equator, but more importantly in this example, also the same distance from the pole.


[superkaempe the gentle giant]
When you come from north and turn east you can follow that great circle,

[Twakkie]
Wrong again. When you come from the north and turn 90 degrees east, the line you are then tracing does not follow that great circle you described (except on the equator). It follows the particular line of latitude at that point where you turn. And that line of latitude does not form a great circle, by definition. The only line of latitude that forms a great circle is in fact the equator.

[superkaempe the gentle giant]
and unlike an latitudinal circle it will at every point at it be perpendicular to the longitudinal circle you came from.

[Twakkie]
Wrong again! Per definition only lines of latitude are perpendicular to lines of longitude, and lines of latitude are not great circles.

Google for "lines of latitude" and you will see what I mean.


[superkaempe the gentle giant]
People often forget that it is possible to start in the direction of a curve and follow a straight line without turning, not only on a plane surface but also on a sphere

[Twakkie]
Lines of latitude are straight lines by definition, because they are parallel to the equator and perpendicular to the lines of longitude! So by turning 90 degrees east in the example and walking straight, you have no choice but to follow the line of latitude!!!

I don't understand why this is so difficult to grasp!

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Re: Continuation of thread
Posted by Hamlet on 21 Aug at 6:12AM
Because it's not true! Superkaempe is right on all counts.

It is now you who are guilty of using Euclidean concepts on the surface of a sphere, namely that because lines of latitude are 'parallel' to the equator they are 'straight' lines. Unfortunately this isn't true. The term geodesic is used to denote a straight line on the earth's surface and it is equivalent to a great circle. There aren't any other types of straight line.

Let me state the problem again

A man starts from the North Pole and walks 6 miles in a straight line (ie on a geodesic). He then faces East and walks 8 miles in a straight line (ie on a geodesic). He then returns to the North pole in a straight line (ie on a geodesic). How many miles did he walk altogether?

Does that help?

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Re: Continuation of thread
Posted by Twakkie on 21 Aug at 1:26PM
No, he is not correct and neither are you.

Each line of latitude is in fact a straight line, but it is not necessarily a geodesic. Only the equator as a line of latitude is also a geodesic. All the other lines of latitude are straight lines, but not geodesics.

Here are some direct quotes from Wikipedia:

(http://en.wikipedia.org/wiki/Latitude)
"All locations of a given latitude are collectively referred to as a line of latitude or parallel, because they are coplanar, and all such planes are parallel to the Equator. Lines of latitude other than the Equator are approximately small circles on the surface of the Earth; they are not geodesics..."

so there goes your theory of parallelity (if there is such a word), or the lack thereof!

(http://en.wikipedia.org/wiki/Line_of_latitude)
"A circle of latitude or parallel is an imaginary east-west circle on the Earth, that connects all locations with a given latitude. It is perpendicular to all meridians."


"East" is a direction from a point of reference. And that direction from a specific point of reference will be along a line of latitude, as these lines are defined as running east-west (see above).

Also from the above we can clearly see that the lines of latitude are perpendicular to all meridiens or lines of longitude.

This whole problem hinges on your interpretation of what "east" is. And you have given more than one meaning or assumption to it in your posing of the riddle.

You first posting, and in the message I am replying to now, you just say the person faces East and walks in a straight line. This is ambiguous. Does this mean he is walking straight east (i.e. along the line of latitude) or in a slightly southeasterly direction (i.e. along the geodesic). Your interpretation is the latter, mine the former. And my first reason, as stated before, is that east is a direction and not a point like north and south are. My second reason is that your path along the geodesic will eventually intersect the equator, which also means you are not truly moving east.

In between these two messages, you refer to a 90 degree east turn before walking on a straight line. I have showed above that all lines of latitude are perpendicular to the meridiens, so a 90 degree turn would also take you along a line of latitude, and not along a geodesic. To travel along the geodesic once you turned east would mean it is not true east, but more southeast.

Each line of latitude is in fact also a straight line, but not with reference to the sphere itself. Only great circles are straight lines with reference to the sphere. Lines of latitude are small circles with reference to a sphere, but still give rise to straight lines.

In terms of two points, travelling along a geodesic would be the shortest route, but this is not what we have here. You did not give two points and ask what is the distance between them. You gave a starting point and a direction, and incorrectly assumed since travelling along a geodesic is the shortest distance between two points, that your given direction will take you along a geodesic. It does not.

It all boils down to your interpretation of east and of a straight line, as said before. And I think you are wrong in your interpretation and you think I am incorrect in mine. Like I said before - Stalemate.

I know I am correct.

If you want to get hung up on semantics about what constitutes a "straight line" and what is "east", then be my guest.

I can see I will not be able to convince you otherwise, and as such it all comes down to a matter of interpretation of the semantics of the riddle as posed.

The problem in your answer comes in when you extrapolate the problem to greater distances. On the equator we both get the same answer, and we agreed on that. At other distances (either greater or less than the equator) we differ. My assumptions hold true for all these relative distances - yours does not. For each distance you travel south (be it more or less than to the equator), you get a different distance back to the north pole, but on the equator the return distance is the same. This is where your argument falls flat. My argument holds true for all distances and for the equator. And this is because of your interpretation of "east" and "straight line".

So lets agree to disagree. You have not even slightly got me to consider your view as being correct, and I suppose its likewise with you. Hopefully this will give rise to some thought, if not for you, then for others also reading this.

I am getting tired of this debate. Interesting as it was, the time has come to close the book and move on.

I will still respond to questions and queries in this regard, but I am no longer going to actively trying to convince you or anyone else that 24 miles is the incorrect answer to your riddle and that it should be 20 miles.

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Re: Continuation of thread
Posted by superkaempe the gentle giant on 21 Aug at 1:53PM
No matter what wikipedia says there is among mathematicians and physicists one and only one accepted definition of a straight line, and it is what I mentioned in another post, the shortest distance between two points and as I pointed out before a curve and its tangent have the same direction in the tangent point, the tangent can be a straight line or even another curve, but an important thing here is that a point has no extent. It is also a well known fact among mathematicians that in spherical geometry parallel lines do not exist even though they do in Euclidian geometry. Also in Euclidian geometry two straight lines that are not parallel only croos each other in one point, in spherical geometry two straight lines gross each other in exactly two points.

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Re: Continuation of thread
Posted by Twakkie on 21 Aug at 4:18PM
OK. Then please provide such proof from all these mathematicians and physicists. I have given links and quotes - to date no one else has...

I have not argued one bit against the fact that a geodesic forms a line which is the shortest distance between two points. I actually agree with that.

The mistake you are making is assuming that your turn east takes you along a geodesic, which in fact it does not. In the riddle you are not moving to a certain point in the shortest possible distance (which would mean you are travelling along a geodesic) - you are starting at a certain point and moving in a line which is not necessarily a geodesic. Your assumption is flawed.

The other mistake you are making with spherical geometry, is that you are assuming that the only straight lines are geodesics or great circles. Small circles are also lines on the surface - they are just not the shortest distance between two points like a geodesic, but they are nevertheless still lines.. Go read the definition of a line on a sphere.

I know great circles can't be parallel to each other, its fairly obvious. But small circles can, and all lines of latitude except the equator are small circles. They are also called "parallels" - go figure! So parallel lines DO in fact exist in spherical geometry, but they are NOT geodesics or great circles but small circles.

Here is a link to the definition of great and small circles:
http://www.pilotsweb.com/navigate/coordi.htm

in short it says the following:
"A GREAT CIRCLE is a circle on a sphere's surface whose plane is passing exactly through the center of the sphere. In other words, a great circle divides a sphere into two symmetrical parts. An arc on a great circle represents the shortest distance between two points on a sphere."

"Any circle on a surface of a sphere which is not a great circle is a SMALL CIRCLE. A SMALL CIRCLE is any circle on a surface of a sphere whose plane is not passing through the sphere's center."

And those planes can be parallel to each other and the equator, as is the case with all lines of latitude.

I await your response.

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Re: Continuation of thread
Posted by superkaempe the gentle giant on 22 Aug at 3:07AM
Take any book with geometrical definitions and axioms for college students, and you will find that there is one and only one straight line connecting two points and since great circles are the straight lines on a sphere then small circles can not be straight lines.
Parallel cicles are circles with a common centre, parallels do not have to be lines.

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Re: Continuation of thread
Posted by Twakkie on 22 Aug at 9:18AM
[had to re-post this since it was deleted]

You are still missing the point.

I AGREE THAT THE SHORTEST DISTANCE BETWEEN TWO POINTS IS ON A GEODESIC!!!

That is not the issue. The question does not ask that you move on the shortest possible distance along a great circle. It simply states a direction from a point. You are incorrectly assuming that since the shortest possible distance is along a great circle that you now have to travel along one. This is the flaw in your argument.

You are not given two points and asked to get there in as short a distance as possible. You are given a point and a direction. Your direction assumption is also incorrect, as your trip along your chosen geodesic takes you southeast and not true east. Only a trip along a parallel or line of latitude ( and I emphasize the word LINE ) will take you true east and continue to take you true east for as long as you care to travel along it!

The issue here is not about the shortest distance between two points. We only have one point and a direction! Not two points! So a geodesic is not necessarily in play here.

And of course a small circle is a line! A line is formed when any plane intersects a sphere, whether it be a great circle or a small circle, it is nevertheless still a line. It might not be the shortest distance between two points on that line, but it nevertheless is still a line with reference to the sphere.

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Re: Continuation of thread
Posted by FragileKitty on 22 Aug at 4:51PM
I believe I have cleared up all the confusion:

http://www.fragilekitty.com/flatland/

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Brilliant!!
Posted by p24601 on 22 Aug at 6:05PM
Great job, well chosen graphics, clear explanations.

If you don't write courseware, or teach in some venue, you should.

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Re: Continuation of thread
Posted by Twakkie on 23 Aug at 7:59AM
Everything you said made sense. You have also put it all together in an idiot-proof package.

You have ignored one thing though...

The original riddle said "face east and walk in a straight line". Then it was later clarified by saying "turn 90 degrees east".

To me they are one and the same.

In your eloquent example, once you turn east and start walking your geodesic, you are either no longer facing east, or if you are still facing east, you are walking like a crab because your direction of travel is no longer east.

You have also turned through the 90 degrees as posted to clarify the original riddle in order to travel along your geodesic. You are turning through more than 90 degrees.

This is what you have left out in your discussion, and this is also why 24 miles as the answer is wrong.

I am going to let this go now. It is like a debate about creation versus evolution. No-one will win the argument.

You interpret things your way and present your answer to fit your theories, and I do likewise.

I don't believe you are correct in your assumptions and application of the theory, and you likewise with me.

I hope this has at least stimulated some thought in others.

And don't misconstrue this as backing down - I still believe that based on the clues given the answer should be 20 and not 24 - but I can not argue this anymore. It is time-consuming and turning out to be a waste of effort.

Sorry. Case closed.

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Re: Continuation of thread
Posted by FragileKitty on 23 Aug at 9:17AM
The original riddle said "face east and walk in a straight line". Then it was later clarified by saying "turn 90 degrees east".

To me they are one and the same.

I agree. The confusing concept is that you can face east, and yet then travel in a straight line and no longer be facing east once you move forward. This apparent contradiction threw me for a loop, too. This has been explained by superkaempe the gentle giant, in mathematical terms, but I admit that unless you learn the math for that it will still sound elusive. He has a very strong background in math, with knowledge far above mine, so I wouldn't dismiss his explanations lightly.

In your eloquent example, once you turn east and start walking your geodesic, you are either no longer facing east, or if you are still facing east, you are walking like a crab because your direction of travel is no longer east.

You're right again. The moment you move forward you are no longer facing east. This is because east is not a straight line on a sphere. On a 2D map it is, but not so on a sphere. Again, that confusing concept of facing east.

You have also turned through the 90 degrees as posted to clarify the original riddle in order to travel along your geodesic. You are turning through more than 90 degrees.

No, you are only turning 90 degrees. On a 2D map, if your "straight path" took you southeast at a diagonal angle (on a line that eventually crosses the equator), then yes, you would be turning more than 90 degrees. But not so on a sphere. Geometry gets a little funny on the surface of a 3D sphere. This was the point in my (attempted) humorous references to Flatlanders. It's very easy to want to apply 2D "truths" to 3D curved surfaces, but unfortunately they don't always work the same.

I'm not interested in endlessly defending my "theories" either. I'm willing to be wrong. Using our brains to investigate logical puzzles like this fascinates me. If I thought you truly were only defending your theories and not considering what I've been saying, I'd be done with this, too. But I respect your passion for participating in this thread in what seems to be a shared consideration to understand the puzzle, and also understand each other's point of view. I know it's frustrating and tiring, especially when you seem to be the minority of the "two sides". I've been there :) But I also admire your willingness to defend the position you believe in, present logical arguments, and not cave in. I think I pretty much understand where you're coming from in your answer and explanations; I agreed with everything you said this time except for the one point about 90 degrees!

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Re: Continuation of thread
Posted by Twakkie on 23 Aug at 11:27AM
OK. Progress. Mutual respect. I like it!

What threw me initially was the "face east" AND "walk in a straight line". You can only do that if you move along the parallel. The 90 degree turn also confirms it. There is no doubt that the angle you are turning to move along the geodesic takes you through 90 degrees and you do not continue to face true east once you start walking. Once turned, you are facing east, and then turning a little bit further along your personal vertical axis to walk further on the said geodesic.

If the riddle just said:
Face east. Now walk in a straight line...

it would all have been sorted and I would agree with you, Hamlet and SuperK 100%.

but it said that little word and...which completely changes the scenario.

We can both see and respect each other's point of view, so I guess it is OK.

In retrospect and despite Hamlet's best intentions, the riddle has turned out to be very sneaky and ambiguous.

This whole argument has turned out to be centred around the interpretation of the clues as opposed to the math involved, or the incorrect application of mathematical principles on either side.

Anyway, I enjoyed your Flatlander montage...gave me quite a chuckle!

And I have learned things about spherical trigonometry I never knew...go figure!

Now, where do I find another riddle to answer?

Cheers!

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Re: Continuation of thread
Posted by superkaempe the gentle giant on 21 Aug at 6:16AM
By definition a straight line is the shortest distance between two points. On a sphere only a great circle fulfill that definition which means that latitude circles are not straight lines.

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Re: Continuation of thread
Posted by Twakkie on 22 Aug at 7:15AM
I will say it again because it does not seem to sink in:

We are not moving from a point to another point in this riddle, so a geodesic is not nessesarily the only line in play here. We are moving from a point in a direction , which is not automatically on a geodesic.

Please find me a link or some other proof - other than your own personal theories, assumptions and conclusions - that states emphatically that a line of latitude is not a line on a sphere. It is not the shortest distance between two points, but it is still a line with reference to a sphere.

Once you have done that, then we can talk about the ambivalence of the riddle with regards to "east" and "90 degrees".

Else it is futile.

I have searched for something along those lines and could not find anything, so you will unfortunately have to provide such proof from a reputable source.

And I will take your lack of such proof as support for the fact that lines of latitude are lines with respect to a sphere.

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Re: Continuation of thread
Posted by superkaempe the gentle giant on 22 Aug at 7:43AM
In the original problem it says we are facing east not going east, the great circle and the small circle have the same direction in the point where they touch each other, the very definition of direction of a curve in a given point is the direction of the tangent in that point, and the great and the small circle have a common tangent in the point where they touch

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Re: Continuation of thread
Posted by Twakkie on 22 Aug at 9:26AM
Still no proof? OK...

Facing east but not going east? Then what is the point of the riddle? Why face east and walk straight if this is not the direction you intend going?

Like I said before, it is all going to boil down to the semantics of "east" and "straight line".

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Re: Continuation of thread
Posted by Hamlet on 22 Aug at 9:37AM
http://mathworld.wolfram.com/SphericalGeometry.html

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Re: Continuation of thread
Posted by Twakkie on 23 Aug at 5:00AM

it does not say anything about small circles, lines of latitude or parallels...

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Re: Continuation of thread
Posted by superkaempe the gentle giant on 23 Aug at 5:56AM
It says there are no parallel lines. From a geometrical point of view small circles are not lines but curves.

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Re: Continuation of thread
Posted by FragileKitty on 21 Aug at 12:47PM
Twakkie,

Do you understand the idea of having a local coordinate system where the Y axis of where you are standing is simply a vertical line from your feet to your head?

Can we agree that to walk in a "straight line" on the surface of a sphere means to not turn left or right; that is, to not rotate about this local Y axis?

If you agree to all this, then the question becomes: When walking along a line of latitude, are you walking in a straight line (without ever turning left or right, without ever rotating about the local Y axis)?

Remember, if you're walking in a straight line, you're taking the shortest distance between two points, which on a sphere's surface is a geodesic (a portion of a great circle). As you said, only the equatorial line of latitude is a great circle.

All this confusion (and believe me, it confused me for quite awhile) stems from the ideas of "facing" east and "traveling" east. It is very hard to grasp the idea of "facing" east and then not traveling east when you walk in a straight line. This is because we imagine a 2D graph of east and west being a horizontal "straight" line, and try to apply that to a sphere. As I said before, a sheet of paper with horizontal straight lines only maps to a cyclinder and retains straight lines. On a sphere all lines not on the equator are warped into curves. If you look at a sphere and "flatten" it into a 2D projection (imagine a picture without any depth), then yes, all the lines of latitude look straight. But the world isn't flat.

On the earth, east and west are not straight lines everywhere. We really shouldn't even say that we "face" east. We should say that we turn 90 degrees counter-clockwise. If we then walk "straight", we'll be following a great circle that is not parallel to any lines of latitude. If we walk "east", we'll travel along a "line" of latitude, which just doesn't happen to be a straight line (except for the equator).

We can't take our 2D idea of east and west and apply it to a sphere's surface. In 3D, we'd need a cylinder for that to work.

-- Reply

               
Re: Continuation of thread
Posted by Twakkie on 21 Aug at 1:36PM
Kitty,

See my detailed response on this issue.

I am now getting tired of all this arguing. It is counter-productive.

For the record - the person walking and his orientation relative to the sphere has got nothing to do with the problem. The problem is about what is "east" and what is a "straight line", and the interpretation thereof.

I know walking "east" in a "straight line" as Hamlet and now also you define it, is not true east, but southeast in the given problem, and continuing on this "straight line" will mean you cross the equator at some point - which means you are moving south while moving east.

In my interpretation you will continue eastwards and if you do not stop, you will end up at the same point you started without crossing the equator twice, which means along a line of latitude around the earth. And this eastwards direction of mine can be neverending. In your scenario you will at some point start moving west and north, which is definitely not east anymore!

Read the other post and we can discuss further if you wish.

-- Reply

     
Re: Triangulation
Posted by FragileKitty on 23 Aug at 9:21AM
Ack. My last post is so far down now it's hard to find, so here it is again in reply to:

Re: Continuation of thread
Posted by Twakkie on 23 Aug at 7:59AM

Everything you said made sense. You have also put it all together in an idiot-proof package.

You have ignored one thing though...

The original riddle said "face east and walk in a straight line". Then it was later clarified by saying "turn 90 degrees east".

To me they are one and the same.

In your eloquent example, once you turn east and start walking your geodesic, you are either no longer facing east, or if you are still facing east, you are walking like a crab because your direction of travel is no longer east.

You have also turned through the 90 degrees as posted to clarify the original riddle in order to travel along your geodesic. You are turning through more than 90 degrees.

This is what you have left out in your discussion, and this is also why 24 miles as the answer is wrong.

I am going to let this go now. It is like a debate about creation versus evolution. No-one will win the argument.

You interpret things your way and present your answer to fit your theories, and I do likewise.

I don't believe you are correct in your assumptions and application of the theory, and you likewise with me.

I hope this has at least stimulated some thought in others.

And don't misconstrue this as backing down - I still believe that based on the clues given the answer should be 20 and not 24 - but I can not argue this anymore. It is time-consuming and turning out to be a waste of effort.

Sorry. Case closed.

-- Reply

Re: Continuation of thread 
Posted by FragileKitty on 23 Aug at 9:17AM

The original riddle said "face east and walk in a straight line". Then it was later clarified by saying "turn 90 degrees east".

To me they are one and the same.

I agree. The confusing concept is that you can face east, and yet then travel in a straight line and no longer be facing east once you move forward. This apparent contradiction threw me for a loop, too. This has been explained by superkaempe the gentle giant, in mathematical terms, but I admit that unless you learn the math for that it will still sound elusive. He has a very strong background in math, with knowledge far above mine, so I wouldn't dismiss his explanations lightly.

In your eloquent example, once you turn east and start walking your geodesic, you are either no longer facing east, or if you are still facing east, you are walking like a crab because your direction of travel is no longer east.

You're right again. The moment you move forward you are no longer facing east. This is because east is not a straight line on a sphere. On a 2D map it is, but not so on a sphere. Again, that confusing concept of facing east.

You have also turned through the 90 degrees as posted to clarify the original riddle in order to travel along your geodesic. You are turning through more than 90 degrees.

No, you are only turning 90 degrees. On a 2D map, if your "straight path" took you southeast at a diagonal angle (on a line that eventually crosses the equator), then yes, you would be turning more than 90 degrees. But not so on a sphere. Geometry gets a little funny on the surface of a 3D sphere. This was the point in my (attempted) humorous references to Flatlanders. It's very easy to want to apply 2D "truths" to 3D curved surfaces, but unfortunately they don't always work the same.

I'm not interested in endlessly defending my "theories" either. I'm willing to be wrong. Using our brains to investigate logical puzzles like this fascinates me. If I thought you truly were only defending your theories and not considering what I've been saying, I'd be done with this, too. But I respect your passion for participating in this thread in what seems to be a shared consideration to understand the puzzle, and also understand each other's point of view. I know it's frustrating and tiring, especially when you seem to be the minority of the "two sides". I've been there :) But I also admire your willingness to defend the position you believe in, present logical arguments, and not cave in. I think I pretty much understand where you're coming from in your answer and explanations; I agreed with everything you said this time except for the one point about 90 degrees!

-- Reply


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